Search for: In the expansion of (1 + x)n ,C1C0+2C2C1+3C3C2+…+nCnCn−1 is equal to In the expansion of (1 + x)n ,C1C0+2C2C1+3C3C2+…+nCnCn−1 is equal to A(n+1)2Bn2Cn(n+1)2DNone of these Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:Since, we know that nCr nCr−1=n−r+1r∴C1C0=n,C2C1=n−12,C3C2=n−23,… Thus, C1C0+2C2C1+3C3C2+…=n+2⋅n−12+3⋅n−23+…+n⋅1n=[n+(n−1)+(n−2)+…+1]=n(n+1)2 Related content Complex Numbers Class 11 Worksheet with Answers CBSE 12th Result 2024 (Out) Today, How to check CBSE Class 12 Marks @cbseresults.nic.in How to use NEET UG College Predictor 2024 to find your dream Medical College Is a Gap Certificate for NEET Repeaters Necessary? General Knowledge Questions With Answers on Islamic CBSE Class 10 Worksheets NEET Rank Predictor 2024: Calculate Your Rank by Marks Why to Choose Infinity Learn NEET Rank Predictor 2024 – The Most Accurate NEET Rank Predictor CBSE Class 10 Science MCQs CBSE Class 9 Science Structure of Atom MCQs