A+B→CH3−O−C(CH3)3→HIX+Y.Correct statement among the following is(If X and Y formation proceeds SN1)

$A + B \to {CH}_{3} - O - C {({CH}_{3})}_{3} \overset{HI}{\to} X + Y .$
Correct statement among the following is(If X and Y formation proceeds SN1)

A
A and B are ${CH}_{3} ONa and {({CH}_{3})}_{3} CBr$
B
X and Y are ${CH}_{3} I and {({CH}_{3})}_{3} COH$
C
X and Y are ${CH}_{3} OH and {({CH}_{3})}_{3} CI$
D
A and B are ${CH}_{3} OH and {({CH}_{3})}_{3} COH$

Solution:

X and Y are ${CH}_{3} OH and {({CH}_{3})}_{3} CI$ . Since SN1 is considered then the intermediate will be carbocation.

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