A+BCH3OC(CH3)3HIX+Y.

Correct statement among the following is(If X and Y formation proceeds SN1)

  1. A

    A and B are  CH3ONaandCH33CBr

  2. B

    X and Y are  CH3IandCH33COH

  3. C

    X and Y are CH3OHandCH33CI

  4. D

    A and B are CH3OHandCH33COH

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    Solution:

    X and Y are CH3OHandCH33CI. Since SN1 is considered then the intermediate will be carbocation.

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