An ideal gas is allowed to expand from 1 L to 10 L against a constant external pressure of 1 bar. The work done in kJ is

An ideal gas is allowed to expand from 1 L to 10 L against a constant external pressure of 1 bar. The work done in kJ is

A
-9.0
B
+10.0
C
-0.9
D
-2.0

Solution:

$\begin{array}{l} W = - P_{ext} (V_{2} - V_{1}) \\ = - 1 bar \times (10 - 1) / i t = - 9 b a r - l i t \\ = - 900 J = - 0.9 kJ . \end{array}$

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