Calculate coagulation value of AlCl3 if for coagulation of 400 ml of a gold sol, 427.2 milli-grams of AlCl3 is required.

  1. A

    8 mm

  2. B

    4 mm

  3. C

    2 mm

  4. D

    7 mm

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    Solution:

    1 litre gold sol will require=1068 mg of AlCl3

    Molar mass of AlCl3=133.5 gm/mole

    mm of AlCl3 required=1068133.5=8 mm

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