Calculate coagulation value of AlCl3 if for coagulation of 400 ml of a gold sol, 427.2 milli-grams of AlCl3 is required.

Calculate coagulation value of $A l C l_{3}$ if for coagulation of $400 m l$ of a gold sol, $427.2$ milli-grams of $A l C l_{3}$ is required.

$1$ litre gold sol will require $= 1068 m g$ of $A l C l_{3}$

Molar mass of $A l C l_{3} = 133.5 g m / m o l e$

$m m$ of $A l C l_{3}$ required $= \frac{1068}{133.5} = 8 m m$

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