Given the following sequence of reactionCH3CH2I→NaCNA→partial hydrolysisOH-B→Br2/NaOHCThe major product 'C' is

A
${CH}_{3} {CH}_{2} {NH}_{2}$
B
${CH}_{3} {CH}_{2} \underset{\underset{O}{II}}{C} - NHBr$
C
${CH}_{3} {CH}_{2} - {COONH}_{4}$
D
${CH}_{3} {CH}_{2} \underset{\underset{O}{II}}{C} - {NBr}_{2}$

Solution:

${CH}_{3} {CH}_{2} I \overset{NaCN}{\to} \underset{A}{{CH}_{3} {CH}_{2} CN} \overset{{OH}^{-}}{\to} \underset{B}{{CH}_{3} {CH}_{2} {CONH}_{2}} \overset{{Br}_{2} / NaOH}{\to} \underset{C}{{CH}_{3} {CH}_{2} {NH}_{2}}$

Given the following sequence of reaction ${CH}_{3} {CH}_{2} I$ $\overset{NaCN}{\to}$ $A$ $\to_{partial hydrolysis}^{{OH}^{-}}$ $B$ $\overset{{Br}_{2} / NaOH}{\to}$ $C$
The major product $' C'$ is

Solution:

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