HCI is produced in the stomach, which can be neutralized by Mg(OH)2 in the form of milk of magnesia. How much Mg(OH)2 is required to neutralize one mole of stomach acid?

  1. A

    29.16 g

  2. B

    34.3 g

  3. C

    58.33 g

  4. D

    68.65 g

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    Solution:

    Mg(OH)2+2HClMgCl2+2H2O
    No. of moles of Mg(OH)2 required for 2 moles of HCI = 1
    No. of moles of Mg(OH)2 required for 1 mole of HCI = 0.5
    Mass of 0.5 moles of Mg(OH)2 = 58.33 x 0.5 = 29.16 g

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