Hydrogen has three isotopes (A), (B) and C). If the number of neutron(s) in (A), (B) and (C) respectively, are (x), (y) and (z), the sum of (x), (y) and (z) is

Hydrogen has three isotopes (A), (B) and C). If the number of neutron(s) in (A), (B) and (C) respectively, are (x), (y) and (z), the sum of (x), (y) and (z) is

  1. A

    4

  2. B

    3

  3. C

    2

  4. D

    1

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    Solution:

    Number of neutrons in protium  11H is zero (x). 
    Number of neutrons in deuterium  12H or 12D is 1 (y). 
    Number of neutrons in tritium  13H or 13T is 2 (z) 
    So, the sum of x, y and z is x + y+2=3 

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