In the reaction, 3Cl2+6NaOH →5NaCl+NaClO3+3H2O , the oxidant and reductant are respectively

In the reaction, $3 {Cl}_{2} + 6 NaOH \to 5 NaCl + {NaClO}_{3} + 3 H_{2} O$ , the oxidant and reductant are respectively

A
${Cl}_{2}, {Cl}_{2}$
B
${Cl}_{2}, NaOH$
C
$NaOH, {Cl}_{2}$
D
$NaOH, NaOH$

Solution:

This is a disproportionation reaction. Chlorine undergoes both oxidation and reduction.

$1) \overset{0}{{Cl}_{2}} \to {Cl}^{- 1} . . . reduction 2) \overset{0}{{Cl}_{2}} \to \overset{+ 5}{Cl} O_{3}^{-} . . . . . oxidation$

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