In transforming 0.01 mole of PbS to PbS04 the volume of 10 volume H2O2 required will be

A
11.2 ml
B
22.4 ml
C
33.6 ml
D
44.8 mi

Solution:

$PbS + 4 H_{2} O_{2} \to \underset{White}{{PbSO}_{4}} + 4 H_{2} O \begin{array}{l} 4 H_{2} O_{2} \to 4 H_{2} O + 2 O_{2} \\ 4 (2 + 32) 2 \times 22.4 litre \\ = 136 g at NTP. \end{array}$

from the above equation we can derive that In transforming 1 mole of $PbS to {PbSO}_{4}$ the volume of 10 volume of $H_{2} O_{2}$ required is 44.8 ml at NTP.

In transforming 0.01 mole of $PbS$ to PbS0₄ the volume of 10 volume $H_{2} O_{2}$ required will be

Solution:

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