The concentrations of acetic acid and sodium acetate is a buffer solution of total moalrity 0.39 M and having a pH of 4.4 if the Ka of acetic acid is  is 1.83×10-5 is

  1. A

    0.26;  0.13

  2. B

    0.13; 0.26

  3. C

    0.30; 0.09

  4. D

    0.18; 0.21

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    Solution:

    Ka=10-4.2=6.31×10-5,log[Salt][Acid]=pH-pKa

    =pH+logKa=4.4+log(1.83×10-5)= 4.4 – 4.7 = - 0.3 

    [Salt][Acid]=10-0.3=0.5  1+[Salt][Acid]=1+0.5

    [Acid]+[Salt][Acid]=1.5 , total  molarity[Acid]=1.50.39[Acid]=1.5

    [Acid]=0.391.5=0.26  [Salt] = 0.39 – 0.26 = 0.13

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