Volume strength of hydrogen peroxide is 22.4. What volume of this sample is required for the oxidation of 3.4 g of hydrogen sulphide?

  1. A

    50 mL

  2. B

    200 mL

  3. C

    100 mL

  4. D

    5 mL

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    Solution:

    H2​S+H2O2​⟶2H2O+S

    34g H2S reacts with 34g H2O2​

    3.4gH2​S reacts with 3.4gH2O2​

    Volume strength 22.4 means 22.4×3.035=67.98g/L

    67.98g are present in one liter. 3.4g are present in

    67.981​×3.4=0.05L=50mL

    correct answer is 1

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