Solution:
H2S+H2O2⟶2H2O+S
34g H2S reacts with 34g H2O2
3.4gH2S reacts with 3.4gH2O2
Volume strength 22.4 means 22.4×3.035=67.98g/L
67.98g are present in one liter. 3.4g are present in
67.981×3.4=0.05L=50mL
correct answer is 1
Volume strength of hydrogen peroxide is 22.4. What volume of this sample is required for the oxidation of 3.4 g of hydrogen sulphide?
H2S+H2O2⟶2H2O+S
34g H2S reacts with 34g H2O2
3.4gH2S reacts with 3.4gH2O2
Volume strength 22.4 means 22.4×3.035=67.98g/L
67.98g are present in one liter. 3.4g are present in
67.981×3.4=0.05L=50mL
correct answer is 1