What is the electronic configuration of Cu2+(Z=29) of least position

What is the electronic configuration of ${Cu}^{2 +} (Z = 29)$ of least position

A
$[Ar] 4 s^{1} 3 d^{8}$
B
$[Ar] 4 s^{2} 3 d^{10} 4 p^{1}$
C
$[Ar] 4 s^{1} 3 d^{10}$
D
$[Ar] 3 d^{9}$

Solution:

$_{29} Cu = [Ar] 3 d^{10} 4 s^{7}, {Cu}^{2 +} = [Ar] 3 d^{9} 4 s^{0}$

Ground state of ${Cu}^{29} = 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{1}$

${Cu}^{2 +} = 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{9}$

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