∫−14 (2x−3)dx is equal to

14(2x3)dx is equal to

  1. A

    32

  2. B

    13

  3. C

    12

  4. D

    0

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    Solution:

    Let I=14(2x3)dx and f(x)=2x3

    then,

    f(x)dx=(2x3)dx=2x223x=x23x=F(x)( say )

    Now, by the fundamental theorem of integral calculus, we get

    I=[F(x)]14=F(4)F(1)=(4)23(4)(1)23(1)=(1612)(1+3)=44=0

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