A box contains 3 white and 2 red balls. If we draw one ball and without replacing the first ball, the probability of drawing red ball in the second draw is

# A box contains 3 white and 2 red balls. If we draw one ball and without replacing the first ball, the probability of drawing red ball in the second draw is

1. A

8/25

2. B

2/5

3. C

3/5

4. D

21/25

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### Solution:

there are two cases arise.
Case I: If 1st ball is white, then probability
Case II: if 1st ball is red, then probability

Required probability $=\frac{3}{10}+\frac{1}{10}=\frac{2}{5}$

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