A box contains 3 white and 2 red balls. If we draw one ball and without replacing the first ball, the probability of drawing red ball in the second draw is

A box contains 3 white and 2 red balls. If we draw one ball and without replacing the first ball, the probability of drawing red ball in the second draw is

  1. A

    8/25

  2. B

    2/5

  3. C

    3/5

  4. D

    21/25

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    Solution:

    there are two cases arise.
    Case I: If 1st ball is white, then probability = 3C1 5C1× 2C1 4C1=620=310
    Case II: if 1st ball is red, then probability  = 2C1 5C1× 1C1 4C1=220=110

    Required probability =310+110=25

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