Solution:
Arrange non-vegeterians in (6 -1)! =5! ways and vegeterian in (5 – 1)! = 4! ways
required number of ways
A man invites 6 non-vegeterian and 5 vegeterian friends for a dinner party. He arrange 6 non-vegeterian friends on one round table and 5 vegeterian friends along another round table. The number of ways this can be done is:
Arrange non-vegeterians in (6 -1)! =5! ways and vegeterian in (5 – 1)! = 4! ways
required number of ways