A man saved Rs 66000 in 20 yr. In each succeeding year after the first year he saved Rs 200 more than what he saved in the previous year. How much did he save in the first year?

A man saved Rs 66000 in 20 yr. In each succeeding year after the first year he saved Rs 200 more than what he saved in the previous year. How much did he save in the first year?

  1. A

    Rs.1450

  2. B

    Rs.1400

  3. C

    Rs.1470

  4. D

    Rs.1480

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    Solution:

    Here, n=20,Sn=66000,d=200

    Let first term is a

            Sn    =n2[2a+(n1)d]        66000    =202[2×a+(201)200]        6600    =2a+19×200        2a    =66003800        2a    =2800        a    =1400

    Hence, he save in the first year is Rs1400.

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