Aset A has 3 elements and another set B has 6 elements. Then 

Aset A has 3 elements and another set B has 6 elements. Then 

  1. A

    3n(AB)6

  2. B

    3n(AB)9

  3. C

    6n(AB)9

  4. D

    0n(ΛB)9

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    Solution:

    n(AB)  cannot exceed  n(A)+n(B) and cannot

    be less than n(B).

     6n(AB)3+6 i.e., 6n(AB)9

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