If the observations 2,4,8 and 16 occur 8, 6,4 and 2 times respectively, then the geometric mean of the observations is

A
8
B
$4 \sqrt{2}$
C
4
D
None of these

Solution:

$∵ we know$

Geometric mean $\begin{array}{l} = \sqrt[n]{x_{1} \times x_{2} \times \dots \times x_{n}} \\ = \sqrt[20]{2^{8} \times 4^{6} \times 8^{4} \times 16^{2}} \\ = \sqrt[20]{2^{8} \times 2^{12} \times 2^{12} \times 2^{8}} \\ = \sqrt[20]{2^{40}} = 2^{\frac{40}{20}} = 2^{2} = 4 \end{array}$

Related content

Test your English Vocabulary

CUET Exam Dates 2024 – Application Form, Fees, Eligibility

CBSE Class 12 IP Answer Key 2024,Informatics Practices Paper Solution For SET 1, 2, 3, 4

CUET UG Cut Off 2024, Category, Universities and Colleges Wise Expected Cut Off

Modal Verbs

Helping Verbs

Letter To Your Friend About Your School Trip

Action Verbs

CUET 2024 – List of Colleges and Participating Universities Accepting CUET Exam Score

SRMJEEE Online Test Series – Practice Papers