If vertices of a triangle are A(1,- 1, Z), B(2,0,- 1) and C(0,2,1), then the area of a triangle is

If vertices of a triangle are A(1,- 1, Z), B(2,0,- 1) and C(0,2,1), then the area of a triangle is

  1. A

    6

  2. B

    26

  3. C

    36

  4. D

    46

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    Solution:

    Now,

    Δxy=12111201021=12|1(02)+1(20)+1(40)|=12|2+2+4|=2

    Δyz=12121011211=12|[1(11)2(02)+1(0+2)]|=12|[2+4+2]|=4

    Δzx=12211121101=12|[2(20)1(11)+1(02)]|=12|[4+22]|=2

     Area of triangle, 

    Δ=Δxy2+Δyz2+Δzx2=22+42+22=24=26

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