Search for: If limx→1 x2−ax+bx−1=5, then a+ b is equal toIf limx→1 x2−ax+bx−1=5, then a+ b is equal toA5B-4C-7D1 Register to Get Free Mock Test and Study Material +91 Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:Given, limx→1 x2−ax+bx−1=5For existence of limit, 1−a+b=0⇒ b=a−1 …(i)∴limx→1 x2−ax+a−1x−1=5 [Using (i)]⇒limx→1 x2−1−a(x−1)x−1=5⇒limx→1 (x−1)(x+1)−a(x−1)x−1=5⇒limx→1 (x−1)(x+1−a)x−1=5⇒limx→1 (x+1−a)=5⇒2−a=5⇒a=−3 and b=−3−1=−4 [Using (i)] ∴a+b=−3−4=−7Post navigationPrevious: ∫0π/2 sinx1+cos2xdx is equal toNext: ∫23 2x2x4+3×2+1dx is equal toRelated content JEE Main 2023 Question Papers with Solutions JEE Main 2024 Syllabus Best Books for JEE Main 2024 JEE Advanced 2024: Exam date, Syllabus, Eligibility Criteria JEE Main 2024: Exam dates, Syllabus, Eligibility Criteria JEE 2024: Exam Date, Syllabus, Eligibility Criteria NCERT Solutions For Class 6 Maths Data Handling Exercise 9.3 JEE Crash Course – JEE Crash Course 2023 NEET Crash Course – NEET Crash Course 2023 JEE Advanced Crash Course – JEE Advanced Crash Course 2023