If limx→1 x2−ax+bx−1=5, then a+ b is equal to

# If $\underset{x\to 1}{lim} \frac{{x}^{2}-ax+b}{x-1}=5$, then  is equal to

1. A

5

2. B

-4

3. C

-7

4. D

1

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### Solution:

Given, $\underset{x\to 1}{lim} \frac{{x}^{2}-ax+b}{x-1}=5$

For existence of limit, $1-a+b=0$

…(i)

$\therefore \underset{x\to 1}{lim} \frac{{x}^{2}-ax+a-1}{x-1}=5$                               [Using (i)]

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