If tan⁡θ+tan⁡2θ+3tan⁡θtan⁡2θ=3,then

If tanθ+tan2θ+3tanθtan2θ=3,then

  1. A

    θ=(6n+1)π18,nI

  2. B

    θ=(6n+1)π9,nI

  3. C

    θ=(3n+1)π9,nI

  4. D

    None of these

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    Solution:

     tanθ+tan2θ+3tanθtan2θ=3 tanθ+tan2θ=3(1tanθtan2θ)    tanθ+tan2θ1tanθtan2θ=3tan3θ=tanπ3 3θ=+π3θ=(3n+1)π9,nI

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