If y=f(x)=1u2+u+1 where u=1x−1 , then the function is discontinuous at x =

If $y = f (x) = \frac{1}{u^{2} + u + 1} where u = \frac{1}{x - 1}$ , then the function is discontinuous at $x =$

$u = \frac{1}{x - 1} is not defined at x = 1$ . Hence,

$y = f (x) = \frac{1}{u^{2} + u + 1}$ is discontinuous at $x = 1 .$

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