If y=f(x)=1u2+u+1 where u=1x−1 , then the function is discontinuous at x =

If y=f(x)=1u2+u+1 where u=1x1 , then the function is discontinuous at x =

  1. A

    1

  2. B

    1/2

  3. C

    2

  4. D

    -2

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    Solution:

    u=1x1 is not defined at x=1. Hence,

    y=f(x)=1u2+u+1 is discontinuous at x=1.

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