If y=f(x)=1u2+u+1 where u=1x−1 , then the function is discontinuous at x =

If  , then the function is discontinuous at

1. A

1

2. B

$1/2$

3. C

2

4. D

-2

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Solution:

. Hence,

$y=f\left(x\right)=\frac{1}{{u}^{2}+u+1}$ is discontinuous at $x=1.$

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