Mathematics In a rhombus ABCD,AC=8cm and BD=6cm , then each side is

$In a rhombus ABCD, AC = 8 cm and BD = 6 cm, then each side is$

Two diagonals divides the rhombus into four congruent right

angles triangles.

From diagram

$Δ A O B$

is a right angled triangle

$A B 2 = A O 2 + B O 2$

$A B 2 = 42 + 32$

$A B 2 = 16 + 9$

$A B 2 = 25$

$A B = 5$

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