The distance of the plane 3x+4y+5z+19=0 from the point (1,-1,1) measured along a line parallel to the line with direction ratios 2,3,1 is

The distance of the plane 3x+4y+5z+19=0 from the point (1,-1,1) measured along a line parallel to the line with direction ratios 2,3,1 is

  1. A

    2352

  2. B

    7152

  3. C

    14

  4. D

    23

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    Solution:

    Line passing through (1,-1,1) is x12=y+13=z11=t

    P(2t+1,3t1,t+1) lies on 3x+4y+5z+19=0

    t=1P(1,4,0)Q(1,1,1)

    PQ=14

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