Search for: The mean of the series a,a+d,a+2d,…,a+2nd, isThe mean of the series a,a+d,a+2d,…,a+2nd, isAa+(n−1)dBa+ndCa+(n+1)dDnone of these Register to Get Free Mock Test and Study Material +91 Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:We haveRequired mean =a+(a+d)+(a+2d)+…+(a+2nd)2n+1=2n+12{2a+(2n+1−1)d}2n+1=a+ndPost navigationPrevious: The general solution of the trigonometrical equation sinx+cosx=1 for n=0,±1,… is given byNext: The AM of the series 1, 2, 4, 8, 16, … , 2n, isRelated content NEET Rank Assurance Program | NEET Crash Course 2023 JEE Main 2023 Question Papers with Solutions JEE Main 2024 Syllabus Best Books for JEE Main 2024 JEE Advanced 2024: Exam date, Syllabus, Eligibility Criteria JEE Main 2024: Exam dates, Syllabus, Eligibility Criteria JEE 2024: Exam Date, Syllabus, Eligibility Criteria NCERT Solutions For Class 6 Maths Data Handling Exercise 9.3 JEE Crash Course – JEE Crash Course 2023 NEET Crash Course – NEET Crash Course 2023