The speed v of a particle moving along a straight line is given by a+bv2=x2 where x is its distance from the origin the acceleration of the particle is

A
$\frac{x}{b}$
B
$\frac{x}{a b}$
C
$a b x$
D
$a x$

Solution:

We have,

$\begin{array}{l} a + b v^{2} = x^{2} \\ \Rightarrow 2 b v \frac{d v}{d x} = 2 x \Rightarrow v \frac{d v}{d x} = \frac{x}{b} \Rightarrow Acceleration = \frac{x}{b} \end{array}$

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The speed $v$ of a particle moving along a straight line is given by $a + b v^{2} = x^{2}$ where $x$ is its distance from the origin the acceleration of the particle is

Solution:

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