The value of cot−1⁡1−sin⁡x+1+sin⁡x1−sin⁡x−1+sin⁡x is

The value of cot11sinx+1+sinx1sinx1+sinx is

  1. A

    π-x

  2. B

    π-x2

  3. C

    π-x3

  4. D

    None of these

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    Solution:

    cot1cos12xsin12x+cos12x+sin12xcos12xsin12xcos12x+sin12x=cot1cot12x=cot1cotπ12x=π12x

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