The value of limx→b x−a−b−ax2−b2, for b>a

The value of limxbxabax2b2, for b>a

  1. A

    14bab

  2. B

    14bba

  3. C

    14aab

  4. D

    1bba

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    Solution:

     We have, 

    limxbxabax2b2=limxbxb(xb)(x+b){xa+ba}=limxb1(x+b){xa+ba}=12b{2ba}=14bba

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