The value of limx→∞ x+3x−1x+3 is - Infinity Learn by Sri Chaitanya

A
$e$
B
$e^{2}$
C
$e^{4}$
D
$1 / e$

Solution:

We have,

$lim_{x \to \infty} {(\frac{x + 3}{x - 1})}^{x + 3} = lim_{x \to \infty} {(1 + \frac{4}{x - 1})}^{x + 3} = e^{lim_{x \to \infty} \frac{4 (x + 3)}{(x - 1)}} = e^{4}$

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