∫xx(1+log⁡x)dx is equal to

# $\int {x}^{x}\left(1+\mathrm{log}x\right)dx$ is equal to

1. A

${x}^{x}$+c

2. B

${x}^{2x}$+c

3. C

${x}^{x}\mathrm{log}x$+c

4. D

$1/2\left(1+\mathrm{log}x{\right)}^{2}$+c

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### Solution:

$I=\int {x}^{x}\left(1+\mathrm{log}x\right)dx$

Put ${x}^{x}=t$, then ${x}^{x}\left(1+\mathrm{log}x\right)dx=dt$

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