A coin is placed on a horizontal platform which under goes vertical simple harmonic motion of angular frequency ω). The amplitude of oscillation is gradually increased. The coin will leave contact with the platform for the first time:

# A coin is placed on a horizontal platform which under goes vertical simple harmonic motion of angular frequency $\mathrm{\omega }$). The amplitude of oscillation is gradually increased. The coin will leave contact with the platform for the first time:

1. A

for an amplitude of $\frac{{\mathrm{g}}^{2}}{{\mathrm{\omega }}^{2}}$

2. B

at the highest position of the platform

3. C

at the mean position of the platform

4. D

for an amplitude of $\frac{\mathrm{g}}{{\mathrm{\omega }}^{2}}$

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### Solution:

The coin will be just leaving the contact at the lowest position when ${\mathrm{m\omega }}^{2}\mathrm{A}\ge \mathrm{mg}⇒\mathrm{A}\ge \frac{\mathrm{g}}{{\mathrm{\omega }}^{2}}$  Register to Get Free Mock Test and Study Material

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