Search for: The solution of the differential equation, dydx=(x−y)2, when y(1)=1 is The solution of the differential equation, dydx=(x−y)2, when y(1)=1 is A−loge1+x−y1−x+y=x+y−2Bloge2−x2−y=x−yC−logc1−x+y1+x−y=2(x−1)Dlogc2−y2−x=2(y−1) Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:Given, dydx=(x−y)2 Let, x−y=t⇒dydx=1−dtdx ∴ 1−dtdx=t2∫dt1−t2=∫dx⇒12loge1+t1−t=x+c12loge1+x−y1−x+y=x+CGiven, y(1)=1∴12loge(1)=C+1⇒C=−1∴ loge1+x−y1−x+y=2(x−1)⇒−loge1−x+y1+x−y=2(x−1) Related content CBSE Class 7 Science Chapter 2 Nutrition in Animals MCQ with Answers Rabindranath Tagore Jayanti 2024 Rahin Ke Dohe Class 9 Question Answers – MCQs Nucleus Diagram for Class 9 Neuron Diagram Class 9 Human Heart Diagram Class 10 CBSE Class 7 Science Chapter 1 Nutrition in Plants MCQ Questions with Answers CBSE Class 9 English Worksheet – The Road not Taken 50+ GK Questions and Answers for Class 8 “Kabir Ki Sakhiyan” MCQ Questions for Class 9 Hindi with Answers Kshitij, Kritika, Sparsh, Sanchayan Bhag 1