Search for: The value of cos2A3−4cos2A2+sin2A3−4sin2A2 is equal to The value of cos2A3−4cos2A2+sin2A3−4sin2A2 is equal to ABCD Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:cos2A3−4cos2A2+sin2A3−4sin2A2=3cosA−4cos3A2+3sinA−4sin3A2=(−cos3A)2+(sin3A)2=1 Related content How to Convert CGPA into Percentage CBSE Class 6 MCQs for All Subjects with Answers CBSE Class 9 English Rain on the Roof Worksheet CBSE MCQs on Crop Production and Management Class 8 with Answers CBSE MCQs On Mole Concept Class 11 With Answers CBSE Class 10 English Dust of Snow Worksheet CBSE Class 7 English Honeycomb Chapter 2 A Gift of Chappals MCQ Questions with Answers Top Career Option and Courses after 12th 2024: Arts, Commerce & Science Students CBSE Class 7 English MCQ Questions with Answers CBSE Class 12 English Lost Spring MCQ with Answers