The number of atoms present in 9.6 × 1011 a.m.u. of oxygen is

  1. A

    8×1012

  2. B

    4×1010

  3. C

    2×1015

  4. D

    6×1010

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    Solution:

    9.6×1011 a.m.u. of oxygen are contained in 9.6×101116=6×1010 atoms of ' O '. 

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