The number of atoms present in 9.6 × 1011 a.m.u. of oxygen is

The number of atoms present in 9.6 × 10¹¹ a.m.u. of oxygen is

A
$8 \times 10^{12}$
B
$4 \times 10^{10}$
C
$2 \times 10^{15}$
D
$6 \times 10^{10}$

Solution:

$9.6 \times 10^{11} a.m.u. of oxygen are contained in \frac{9.6 \times 10^{11}}{16} = 6 \times 10^{10} atoms of ' O'.$

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