The volume of oxygen liberated from 0.68gm of H2O2 is 

  1. A

    112ml

  2. B

    224ml

  3. C

    56ml

  4. D

    336ml

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    Solution:

    We know that

    2H2O22H2O+O2 2×34g             22400ml 2×34gm=68gm of H2O268gm of H2O222400miO2

    0.68gm of H2O222400×0.6868=224ml

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