∫041π/2 sin⁡xdx is equal to - Infinity Learn by Sri Chaitanya

Solution:

sin x is periodic function with period $2 π$

$\begin{array}{l} I = \int_{0}^{41 π / 2} \sin xdx = \int_{0}^{π / 2} \sin xdx + \int_{π / 2}^{π / 2 + 20 π} \sin xdx \\ I = 0 + \int_{0}^{π / 2} \sin xdx = 1 \end{array}$

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