If ∫0π xf(sin⁡x)dx=A∫0π/2 f(sin⁡x)dx ,then A  is

# If ${\int }_{0}^{\pi } xf\left(\mathrm{sin}x\right)dx=A{\int }_{0}^{\pi /2} f\left(\mathrm{sin}x\right)dx$ ,then $A$  is

1. A

$2\pi$

2. B

$\pi$

3. C

$\pi /4$

4. D

0

Register to Get Free Mock Test and Study Material

+91

Verify OTP Code (required)