If ∫x71−x25dx=1λx81−x24+C then λ  is equal to

If x71x25dx=1λx81x24+C then λ  is equal to

  1. A
  2. B
  3. C
  4. D

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    Solution:

    we have,

    I=x71x25dx=sin7θ1sin2θ5cosθdθ, where x=sinθ=tan7θsec2θdθ=tan8θ8+C=18x81x24+Cλ=8

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