Let z and w be complex numbers such that z-+iω-=0 and arg⁡(zω)=π, then arg z=

$\begin{array}{l} \bar{z} = - i \bar{ω} \Rightarrow z = i ω \\ \Rightarrow arg z = \arg i + \arg ω = \frac{π}{2} + \arg ω \end{array}$

But $\arg (z ω) = π \Rightarrow \arg ω = π - \arg z$

Now, $\arg z = \frac{π}{2} + \arg ω$

$\arg z = π = a rg ω$

Adding (i) and (ii), $2 \arg z = \frac{3 π}{2}, \arg z = \frac{3 π}{4}$

Let z and w be complex numbers such that $\bar{z} + i \bar{ω} = 0$ and $\arg (z ω) = π$ , then arg z=