limx→0 3x+|x|7x−|x|, is

 limx03x+|x|7x|x|, is

  1. A

    2

  2. B

    16

  3. C

    0

  4. D

    does not exist

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    Solution:

    We have,

    limx03x+|x|7x5|x|=limx03xx7x+5x=16

    and, limx0+3x+|x|7x5|x|=limx03x+x7x5x=2

    So, limx03x+|x|7x5|x| does not exist. 

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