limx→∞ 1−4x−13x−1 is equal to

$lim_{x \to \infty} {(1 - \frac{4}{x - 1})}^{3 x - 1}$ is equal to

A
$e^{12}$
B
$e^{- 12}$
C
$e^{4}$
D
$e^{3}$

Solution:

We have to find

$lim_{x \to \infty} {(1 - \frac{4}{x - 1})}^{3 x - 1}$

$= lim_{x \to \infty} {(1 + \frac{(- 4)}{x - 1})}^{3 x - 1} = e^{{lim}_{x \to \infty}^{} - 4 \frac{(3 x - 1)}{x - 1}} = e^{- 12}$

Related content

JEE Main 2023 Question Papers with Solutions

JEE Main 2024 Syllabus

Best Books for JEE Main 2024

JEE Advanced 2024: Exam date, Syllabus, Eligibility Criteria

JEE Main 2024: Exam dates, Syllabus, Eligibility Criteria

JEE 2024: Exam Date, Syllabus, Eligibility Criteria

NCERT Solutions For Class 6 Maths Data Handling Exercise 9.3

JEE Crash Course – JEE Crash Course 2023

NEET Crash Course – NEET Crash Course 2023

JEE Advanced Crash Course – JEE Advanced Crash Course 2023