Statement-1: The coefficient of the term of independent of x in the expansion of x+9x+6n is 3n(2n)!n!n!Statement-2: The coefficient of xr in the expansion of (1+x)n is nr

A
STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is a correct explanation for STATEMENT-1
B
STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is NOT a correct explanation for STATEMENT-1
C
STATEMENT-1 is True, STATEMENT-2 is False
D
STATEMENT-1 is False, STATEMENT-2 is True

${(x + \frac{9}{x} + 6)}^{n} = {(\frac{x^{2} + 6 x + 9}{x})}^{n} = \frac{(3 + x)^{2 n}}{x^{n}}$

$= \frac{3^{2 n}}{x^{n}} {(1 + \frac{x}{3})}^{2 n}$

$∴$ Coefficient of the term independent of $x {(x + \frac{9}{x} + 6)}^{n}$

$= 3^{2 n} [Coefficient of x^{n} in the expansion of {(1 + \frac{x}{3})}^{2 n}]$

$= 3^{2 n} (\begin{matrix} 2 n \\ n \end{matrix}) {(\frac{1}{3})}^{n} = \frac{3^{n} (2 n)!}{n! n!}$ [Using statement -2]

Statement-1: The coefficient of the term of independent of x in the expansion of ${(x + \frac{9}{x} + 6)}^{n}$ is $\frac{3^{n} (2 n)!}{n! n!}$
Statement-2: The coefficient of x^r in the expansion of $(1 + x)^{n}$ is $(\begin{array}{l} n \\ r \end{array})$