The surface area of a sphere when its volume is increasing at the same rate as its radius, is

# The surface area of a sphere when its volume is increasing at the same rate as its radius, is

1. A

1

2. B

$1/2\sqrt{\pi }$

3. C

$4\pi$

4. D

$4\pi /3$

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### Solution:

Let be the surface area and be the volume of

$\frac{dV}{dt}=\frac{dr}{dt}$                                     [Given]