The surface area of a sphere when its volume is increasing at the same rate as its radius, is

The surface area of a sphere when its volume is increasing at the same rate as its radius, is

  1. A

    1

  2. B

    1/2π

  3. C

    4π

  4. D

    4π/3

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    Solution:

    Let S be the surface area and V be the volume of 

    sphere of radius r. Then, 

      dVdt=drdt                                     [Given] 

     r=12π                                           [See illustration 2] S=4πr2S=1

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