The value of ∫0π |cos⁡x|dx is - Infinity Learn by Sri Chaitanya

Solution:

We have,

$\begin{array}{l} I = \int_{0}^{π} | \cos x | d x = \int_{0}^{π / 2} | \cos x | d x + \int_{π / 2}^{π} | \cos x | d x \\ I = \int_{0}^{π / 2} \cos x d x - \int_{π / 2}^{π} \cos x d x = [\sin x]_{0}^{π / 2} - [\sin x]_{π / 2}^{π} \\ I = (1 - 0) - (0 - 1) = 2 \end{array}$

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