Search for: The value of cos2A3−4cos2A2+sin2A3−4sin2A2 is equal to The value of cos2A3−4cos2A2+sin2A3−4sin2A2 is equal to ABCD Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:cos2A3−4cos2A2+sin2A3−4sin2A2=3cosA−4cos3A2+3sinA−4sin3A2=(−cos3A)2+(sin3A)2=1 Related content Appreciation Words Wave Optics Mind Map Alternating Current Mind Map for Class 12, JEE & NEET Paramedical Courses After Class 10 Top Courses After 12th Science with PCM, PCB and PCMB Subject Change Application in School and College CBSE Class 10 Result 2024: Is the Release Date Early? Check Expected Schedule Mizoram NEET Merit List 2023 Government Jobs After 12th Arts Stream Chhattisgarh NEET UG Merit List 2023