The value of limx→2a x−2a+x−2ax2−4a2, is 

The value of limx2ax2a+x2ax24a2, is 

  1. A

    1a

  2. B

    12a

  3. C

    a2

  4. D

    2a

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    Solution:

    We have, 

    limx2ax2a+x2ax24a2=limx2ax2a+x2ax+2a(x2a)(x+2a)=limx2a1+x2a(x+2a)(x+2a)=14a=12a

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