Two sides of a parallelogram are along the lines,x+y=3 and x−y+3=0.If its diagonals intersectat (2, 4), then one of its vertex is

# Two sides of a parallelogram are along the lines,If its diagonals intersectat (2, 4), then one of its vertex is

1. A

(3, 6)

2. B

(2, 6)

3. C

(2, 1)

4. D

(3, 5)

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Solving (i) and (ii), we get $x=0,y=3$
$\therefore$ Coordinates of $A$ are.
Now,  $\frac{{x}_{1}+0}{2}=2$