value of tan−1⁡sin⁡2−1cos⁡2 is

value of tan1sin21cos2 is

  1. A

    π21

  2. B

    1π4

  3. C

    2π2

  4. D

    π41

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    Solution:

    sin21cos2=1sin2cos2=(cos1sin1)2(cos1+sin1)(cos1sin1)=cos1sin1cos1+sin1=1tan11+tan1=tanπ41=tan1π4tan1sin21cos2=tan1tan1π4=1π4

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