∫x2−1xx4+3×2+1dx is equal to

x21xx4+3x2+1dx is equal to

  1. A

    logex+1x+x2+1x2+3+C

  2. B

    logex1x+x2+1x23+C

  3. C

    logex+x2+3+C

  4. D

    none of these

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    Solution:

    We have,

    I=x21xx4+3x2+1dx=11x2x2+3+1x2dx I=1x+1x2+12dx+1x I=logx+1x+(x+1x)2+1

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