A particle moves such that its acceleration a is given by a = – bx. The period of oscillation is:

A particle moves such that its acceleration a is given by a = - bx. The period of oscillation is:

A
$2 π \sqrt{b}$
B
$\frac{2 π}{\sqrt{b}}$
C
$\frac{2 π}{b}$
D
$\sqrt{(\frac{2 π}{b})}$

Solution:

In SHM

$a = ω^{2} x$
$\Rightarrow ω^{2} = b \Rightarrow T = \frac{2 π}{\sqrt{b}}$

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